For the same cross: BbTt x bbTt a. Using the Probability Method illustrated in lecture, break the complex two-gene cross into two simple single-gene crosses (note that the Probability Method can be used if it is known that the alleles of the different genes Assort Independently) b. Show the expected genotypic and phenotypic ratios for each of the simple single-gene crosses.

Answer and Explanation:

cross: BbTt x bbTt

Cross for B gene

Parental ) Bb   x   bb

Gametes) B   b   b   b

Punnet square)  B     b

                  b     Bb    bb

                  b     Bb    bb

F1) Genotypic proportion: 2/4=1/2 Bb : 2/4=1/2 bb

     Genotypic ratio 1:1

     Phenotypic proportion: 2/4=1/2 B- : 2/4=1/2 bb

     Phenotypic ratio   1:1

Cross for T gene

Parental ) Tt   x   Tt

Gametes) T  t     T   t

Punnet square) T       t

                  T     TT    Tt

                  t      Tt    tt

F1) Genotypic proportion 1/4 TT

                                          2/4 Tt

                                          1/4 tt

     Genotypic ratio  1 : 2 : 1

      Phenotypic proportion: 3/4 T-

                                              1/4 tt

     Phenotypic ratio 3 : 1

answer: if she breaths she a thho

explanation:

the level of progesterone is low at the pre-ovulatory phase of the cycle but it gradually increases and the levels are high at the luteal phase. if pregnancy occurs, the level of progesterone will be high throughout the pregnancy.

if egg is fertilized and the mother gets pregnant, progesterone starts preparing the uterus for the implantation. it starts building up the lining of uterus and make it hostile of the period of pregnancy.