". what would be the net gain of atp from the breakdown of ten molecules of glucose under aerobic conditions? 10
20
40
360
2. the krebs cycle does not occur if ?
oxygen is present.
oxygen is not present.
glycolysis occurs.
carbon dioxide is present.
3. in the krebs cycle, the carbon atoms in a three-carbon molecule are released in.
one molecule of water.
three molecules of oxygen.
three molecules of carbon dioxide.
one molecule of glucose.
4. what process do the arrows for oxygen going in and water coming out represent in figure 9–2 diagram of the mitochondria? "

1. option D, 360

2. Option A, oxygen is present

3. Option C, three molecules of carbon dioxide.

4. Electron transport chain

Explanation:

1. In break down of one molecule of glucose, 36 molecules of ATP are released thus break down of ten molecules of glucose will release 360 molecules of ATP.

2. In case if oxygen is present in the kerb cycle , then the pyruvic acid oxidizes itself and loses a carbon dioxide and forms acetyl coenzyme A (CoA)

3. The pyruvic acid (containing three molecule of carbon) formed with in a kerb cycle releases its three carbon in the form of three molecules of carbon dioxide

4. The structure in the image is mitochondria and the process is ETC where energy molecules are formed at the end of the process.

hydroxyl -oh

alcohols, always polar, can form hydrogen bonds with h2o molecules

carboxyl -cooh  

cargoxylic acids, has acidic properties which is a source of hydrogen ions, found in cells in ionized for with a charge of oh-1

carbonyl > co

ketone if within skeleton, aldehyde if group is at the end of skeleton, k & a may be structural isomers, it determines 2 sugars (ketose & aldose)

amino -nh2

amines, acts as a base, it can pick up h+ ions from surrounding solution, ionized with charge of 1+

methyl ch2

addition to rna/dna affects and gene expression

phosphate -opo3 ²⁻

organic phosphates, contributes to negative charge to, molecule that it is a part of, and potential to react with h20

sulfhydryl -sh

thiols, cross-linking stabilize the protein, and it is structure

why do you want to cheat? i dont take it, so i dont know.

explanation:

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