5. If a 180 kg race car starts a race from rest and gets up to a speed of 125 m/s in 18 s, what is the
force applied by the engine of the racecar?
I

1250N

Explanation:

Th force applied by the engine of this race car can be calculated using the formula: F = m × a

Where, F= force in Newtons (N)

m = mass in kilograms

a= acceleration in m/s^2

The mass of the race car is known (180kg). To find the acceleration (a), we divide the speed or velocity by the time taken i.e. a = v/t

Hence, a = 125/18

a = 6.9444m/s^2.

We can then find the force (F) by saying F= 180 × 6.944444

F = 1250Newtons.

1. (1.2kw)x(15/60hours) = .3kwh --> a

2. (5kw)x(90/60hours)x(8cents/kwh) = $0.60 --> d

3. microwave --> 1200 watts = (1.2kw)x(6/60hours) = .12kwh

coffee-maker --> 900 watts = (.9kw)x(10/60hours) = .15kwh

therefore, it requires more energy for the coffee-maker to do the same amount of work.

so the answer is a.

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hope i

-lavira : )