You have sampled a population in which you know that the percentage of the homozygous recessive genotype (aa) is 25%. Calculate the frequency of the "A" allele. *
1 point
0.5
0.4
0.25
0.6

.5

Explanation:

Remember that p = dominant allele, q = recessive allele. Use the Hardy-Weinberg equations:

p^2 + 2pq + q^2 = 1      (AA + Aa + aa = 1)

So aa = q^2. Take the square root, and we'll have just q by itself.

√a^2 = √.25 = .5

So the frequency of the a allele (recessive) = .5.

p + q = 1

p + .5 = 1

p = .5

The frequency of the A allele is .5.

step 1 ammonium can be absorbed by plants, but some is converted into nitrates which are better for plants to absorb. this is called nitrification. 2. step 2 the deer eats the plants and uses the nitrogen-containing proteins for cell growth. 3. step 3 bacteria in the soil conduct nitrogen fixation to convert nitrogen gas from the atmosphere into ammonium. 4. step 4 some of the nitrates are absorbed back into plants, but denitrification breaks down the nitrates into nitrogen gas released back into the atmosphere. 5. step 5 nitrogen is found in the urine, which gets broken down into ammonium through the process of ammonification. 6. step 6 plants absorb the ammonium and begin assimilation, the process to add the nitrogen to protein.

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