Select the correct answer. A particular population of chickens has a frequency for the dominant allele as 0.70 and a frequency for the recessive allele as 0.30. Which expression is the correct way to calculate the frequency of individuals that are heterozygous?

A.
(0.70) × (0.30)
B.
(0.70) – (0.30)
C.
2 × (0.70) × (0.30)
D.
2 × (0.70 – 0.30)

the frequency of heterozygous = 2 *0.7 * 0.3

Explanation:

therefore it is answer c

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