. g Determine the number of moles in 0.05 µg of a 300 bp insert DNA. There are 660 g/mol-bp. What is the molar ratio of insert to vector if you have 10 ng of vector that is 2686 bp?

a. 2.4 x 10^-24 mol

b. 5.4 x 10^4

Explanation:

a. Mass of DNA (of 0.05µg)= 0.05µg x number of base pairs x 650Da

=0.05x300x650Da

(1 Da=1.67x10-24g)

=9750 x 1.67 x 10^-24

=16282.5 x 10^-19µg =1.62 x10^-21 g

No. of moles of insert DNA=mass of DNA(in g)/mass of one mole in g/mol

=1.6 x 10^-21g/660 g/mol

=2.4 x 10^-24 mol

Hence, moles of the insert DNA is calculated as 2.4 x 10^-24

b.

First of all, let us determine number of moles of vector to calculate the molar ratio.

No. of moles of vector=10 x 10^-9 x 2686 x 650 x 1.67 x 10-24/660

=2.68x6.5x1.67x10-27/660

=4.4 x 10^-29 mol

Molar ratio of insert to vector=2.4 x 10^-24/4.4x10^-29

=5.4 x 10^4

So, the molar ratio of the vector and insert as per the data is calculated as 5.4 x 10^4