An individual who is heterozygous for two linked genes (with alleles A, a and B, b) is crossed with an AB/ab individual, and among the progeny are: 14 AB/ab 36 Ab/ab 34 aB/ab 16 ab/ab What is the frequency of recombination

The correct answer is - 0.30

Explanation:

In case of the same alleles, there will be only one type of gametes as there is no repulsion takes place while in heterozygous 4 types of gametes will form due to repulsion.

Always less number shows recombinant. A higher number shows parental. Since the linkage is possible just when removing between the gens is under 50 So, the number of recombinants are:

16+14 = 30

then:

Recombination recurrence = number of recombinants/Total offspring

Recombination Frequency = 30/100 = 0.30

Thus, the correct answer is - 0.30

the solute can move "downhill," from regions of higher to lower concentration, relying on the specificity of the protein carrier to pass through the membrane. this process is called passive transport or facilitated diffusion, and does not require energy.