Find the heat released in cooling 10g of water at 100C down to 25C

]To calculate the amount of heat entering or leaving a system, the equation  

Q

=

m

c

Δ

T

is used.

Explanation:

m = mass (in grams)

c = specific heat capacity (J/g°C)

ΔT = change in temperature (°C)

Here, we will use the specific heat capacity for liquid water which is 4.19 J/g°C.

The mass given is 25.0 grams.

As for the change in temperature, I will assume that it start off at room temperature, 25°C.

25

°

C

−

0

°

C

=

25

°

C

Q

=

m

c

Δ

T

Q

=

25

g

r

a

m

s

⋅

4.19

J

g

°

C

⋅

25

°

C

Q

=

2618.75

J

Take into account significant figures and the answer should be

2.6

⋅

10

3

J

Answer link

if you add everything up correctly you should get 69 i got this because 50 plus 19 is it

the potatoes have high sugar concentrations and although these potatoes were different we could seethe effects that their sugar concentrations had in different environments. for example, the potatoes in sample a, were placed in pure water. this created a hypertonic environment and caused the potatoes to draw in water from its surroundings. we saw the opposite happen with the potatoes in sample b when placed in the sodium chloride solution. the potatoes in this case were in a hypotonic solution and therefore lost water to their surroundings.