In a salt marsh in Georgia, the quantity of solar radiation reaching the ground during the summer is 7,000,000cal/m2/day. The gross productivity of the producers in the salt marsh (mostly microscopic algae) is 0.0040 g/cm2/day. The average rate of respiration (the respiration requirement) is 35% of the gross primary productivity. Ecologists have found that 1 gram of salt marsh producers (the algae) is equivalent to 2,920 calories. Calculate the net primary productivity of the system, in g/m2/day. (remember, 1 m2 = 10,000 cm2)

Answer:

NPP=26 g/m²/day

Explanation:

Important data:

1 m² = 10,000 cm²NPP = GPP - Respiration NPP= Net primary productivity of a systemGPP= Gross productivity of the producers

Available Data:

GPP=0.0040 g/cm²/dayRespiration rate= 35% of the gross primary productivity

We need to calculate the NPP, which equals GPP - Respiration rate.

The respiration rate is 35% of the GPP. This is:

100% GPP 0.004 g/cm²/day

35% GPP X = (35 x 0.004)/100 = 0.0014 g/cm²/day

Now that we know the values of GPP and respiration rate, we can calculate the NPP.

NPP = GPP - Respiration

NPP = 0.004 g/cm²/day - 0.0014 g/cm²/day

NPP = 0.0026 g/cm²/day

Now we also know the NPP, but this value is calculated in g/cm²/day, and we need to calculate it in g/m²/day, so if 1 m² = 10,000 cm², then:

1 cm² 0.0026 g/cm²/day

10,000cm²X = (10,000 x 0.0026)/1 = 26 g/m²/day

                                                     

This is what i found on google“ the monomers combine with each other via covalent bonds to form larger molecules known as polymers. in doing so, monomers release water molecules as byproducts. this type of reaction is known as dehydration synthesis, which means “to put together while losing water. in the process, a water molecule is formed.” i hope this you

The answer is ozone layer.