A lab technician is preparing agar medium. The medium requires 21 grams (g) of agar, 500 mg of dextrose, 3 dg of sodium, and 1 cg of potassium per 1,000 milliliters
(mL) of distilled water.
What is the total weight in g of the dry ingredients?

21.81grams

Explanation:

According to the question, an agar medium requires the following ingredients: 21 grams (g) of

agar, 500 mg of dextrose, 3 dg of sodium, and 1 cg of potassium per 1,000 milliliters (mL) of distilled water.

Hence, the dry ingredient contain 21grams (g) of agar, 500milligrams (mg) of dextrose, 3decigrams (dg) of Sodium, and 1centigrams (cg) of pottasium.

We need to convert all units (not in grams (g)) to grams.

1grams = 1000milligrams

500 milligrams = 500/1000

= 0.500grams.

1grams = 10decigrams

3decigrams = 3/10

= 0.3grams

1grams = 100centigrams

1centigrams = 1/100

= 0.01 grams

Therefore, we have 21g, 0.500g, 0.3g, and 0.01g

The total dry weight of the ingredients will be:

21 + 0.500 + 0.3 + 0.01

= 21.81grams

as the gila monster consumes the eggs or young of the desert cottontail and gambel's quail, thus its main food supply is only accessible for a restricted time duration every year. however, for this, the gila monsters exhibit three adaptations, which elevate their survival rate in the desert condition.  

first, is that they possess huge bodies, and can consume greater concentrations of food during a small period. secondly, they require to feed infrequently as they can accumulate fat in their tails. ultimately, their rate of metabolism is very low, so that they can burn their reservoirs of fat gradually.  

because they are eaten by the frog and the frog getseaten by the snake and the snake by the eagle