You are required to make 10mL of a 0.5M solution of HCl. Your stock solution of HCl is 90M. Using distilled water (dH2O) as a solvent, how much of each component will you need to make the desired final solution?

0.0556 mL of 90 M HCl would be taken and 9.944 mL distilled water added to make 0.5 M, 10 mL HCl solution.

Explanation:

From the dilution equation:

Initial molarity (m1) x initial volume (v1) = final molarity (m2) x final volume (v2).

In this case, m1 = 90 M, v1 = ?, m2 = 0.5 M, and v2 = 10 mL

v1 = m2 x v2/ m1 = 0.5 x 0.01/90 = 0.0000556 L

v1 = 0.0556 mL

This means that the initial volume of 90 M HCl to be taken is 0.0556 mL. Since the final volume to be prepared is 10 mL,

 10 - 0.0556 = 9.944 mL

Hence, 0.0556 mL of 90 M HCl would be taken and 9.944 mL distilled water added to make 0.5 M, 10 mL HCl solution.

the correct answer is b. possesses the characteristic of compartmentalization of organelles, wherein the organelles are bound by membranes.

explanation:

meiosis is the correct answer