Please provide details for this problem. I got 3.24; therefore accept the null hypothesis. The trait for round peas (R) is dominant to wrinkled peas (r), and yellow peas (Y) is dominant to green peas (y). A dyhbrid cross between two heterozygous pea plants is performed (RrYy x RrYy). The following results are observed:
104 round yellow
27 round green
27 wrinkled yellow
2 wrinkled green
What is the chi-square value for this experiment to two decimal places?
For the chi-square calculated, do you accept the null hypothesis? Yes or No

See the answer below

Explanation:

The Chi-square () is calculated by the formula:

= where O = observed frequency and E = expected frequency

A standard dihybrid cross is expected to give 9:3:3:1 phenotypic ratio.

Phenotype               O                  E                                  

Round yellow          104       9/16 x 160 = 90           = 2.18

Round green            27        3/16 x 160 = 30           = 0.30

wringled yellow         27        3/16 x 160 = 30           = 0.30

wrinkled green          2          1/16 x 160 = 10               = 6.40

Total   value to two decimal places = 9.18

Degree of freedom = (n-1) = 4 -1 = 3

Critical   value at 95% probabillity level = 7.815

Since the calculated   si more than the critical   value, the null hypothesis is rejected.

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explanation:

1. dermis

2. chemical

3. urine

4. viruses

5. antibodies