Answers: 2
![pH=-log([H^+])](/tpl/images/0779/9028/79766.png)
![[H^+]=10^{-pH}](/tpl/images/0779/9028/2646c.png)
![[H^+]_{pH=7}=10^{-7}=1x10^{-7}M](/tpl/images/0779/9028/fa550.png)
![[H^+]_{pH=4}=10^{-4}=1x10^{-4}M](/tpl/images/0779/9028/86b76.png)
![\frac{[H^+]_{pH=4}}{[H^+]_{pH=7}} =\frac{1x10^{-4}M}{1x10^{-7}M}\\ \\\frac{[H^+]_{pH=4}}{[H^+]_{pH=7}}=1000](/tpl/images/0779/9028/61b1d.png)
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