A. Assume that the mass of a person is 70 kg and that 8% of the body mass is blood. If the density of blood is 1.055 g/mL, what is the blood volume? B. Assume that the hematocrit ratio is 0.45. What is the plasma volume in this person? C. Assume that the average life span of the red blood cell is 120 days. What volume of packed red blood cells is being destroyed each day? This corresponds to what volume of whole blood? On average, what volume of whole blood is being made each day? D. Assume that the hemoglobin concentration in the whole blood is 16 g%. How much hemoglobin is degraded each day? E. The molecular weight of hemoglobin is 66,600 g mol−1 and each hemoglobin binds four Fe atoms. How much iron is liberated from hemoglobin each day? Give the answer in mg/day and mol/day. F. The molecular weight of bilirubin is 584.7 g mol−1. How much bilirubin is liberated from hemoglobin each day in this person, in mg/day? G. From Part A and Part D, calculate the total amount of hemoglobin in the blood. From this calculate the total amount of iron in the blood.

A. Volume of blood = 5308.06 mL

B. Plasma volume = 2919.43 mL

C. Volume of packed red cells destroyed daily = 19.91 mL

This corresponds to 0.37% of whole blood volume

Volume of whole blood made daily = 44.24 mL

D. Amount of hemoglobin degraded daily = 7.08 g/day

E. Amount of iron liberated from hemoglobin daily = 24 mg/day or 0.00043 mol/day

F. Amount of bilirubin liberated = 62 mg/day

G. Total amount of hemoglobin in blood = 849.3 g of hemoglobin

Total amount of iron in blood = 2.89 g of iron

Explanation:

A. Volume = mass/density

mass = 0.08 * 70 kg * 1000g/1 kg  = 5600 g; density of blood = 1.055 g/mL

volume of blood = 5600 g/1.055 g/mL = 5308.06 mL

B. Plasma volume = total blood volume * (1 - hematocrit)

Plasma volume = 5308.06 * (1 - 0.45) = 2919.43 mL

C. Volume of packed red cells = 0.45 * 5308.06 = 2388.63 mL

Since average lifespan is 120 days, volume of red blood cells destroyed daily = 2388.63 mL / 120 = 19.91 mL

This corresponds to (19.91 mL/5308.06 mL) * 100% = 0.37% of whole blood volume

Since volume of red cells destroyed daily = volume produced daily

Ratio of whole blood to red cells = 1 : 0.45

Volume of whole blood made daily = 19.91mL * 1/0.45 = 44.24 mL of whole blood daily.

D. Hemoglobin concentration = 16 g/dL = 16 g/100 mL = 0.16 g/mL

Amount of hemoglobin degraded daily = 0.16 g/mL * 44.24 mL = 7.08 g/day

E. molar mass of iron atom, Fe = 56 g/mol

Four iron atoms will have a mass of 56 * 4 = 224g

percentage mass of four Fe atoms in hemoglobin = 224/66600 * 100% = 0.34%

amount of iron liberated from hemoglobin daily = 7.08 * 0.34% = 0.024 g/day = 24 mg/day

moles of iron per day = 0.024/56 g/mol = 0.00042 mol/day

F. Amount of bilirubin liberated = 7.08 g * 584.7/66600 = 0.062 g/day = 62 mg/day

G. Total amount of hemoglobin in blood = 0.16 g/mL * 5308.06 mL = 849.3 g of hemoglobin

Total amount of iron in blood = 0.34% * 849.3 = 2.89 g of iron

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