If the fatty acid palmitate (16:0) radiolabeled with 14C in C-16 were metabolized by mammalian cells under anaerobic conditions, what compounds would be tagged with 14C and in what position

The options are missing from the question,

Below are the options.

A) Tag would be CO2

B) Acetate in C-2

C) 1 uvate in C-3

D) pyruvate in C-3

E) oxaloacetate on C-1

F) palmitate in C-16

The correct answer to the question is option B

ACETATE IN C-2

If palmitate (16:0) which is a fatty acid radiolabeled with 14C in C-16, when metabolized under anaerobic conditions by mammalian cells,the compound that will be tagged with 14C will be ACETATE and the position it will be will be C-2

In an anaerobic condition, anaerobic CoA which is formed after the oxidation of fatty acid will now move into the Kreb cycle as a result of oxygen deficiency, taking the form of acetate,it will enter cytosol and will further be used for other purposes.

the answer is

c. parental

a plastic spoon that has a temperature of 78° f is placed into a bowl of soup that has a temperature of 84° f. which of these correctly describes what will happen?

energy as heat moves from the soup to the spoon.