An animal cell is placed in an aqueous solution. The cell has a solute concentration of 6%, while the aqueous solution has a solute concentration of 18%. What will happen to the cell? * a. The cell will swell with solutes b. The cell will swell with water c. The cell will shrivel from losing solutes d. The cell will shrivel from losing water

d.The cell will shrivel from losing water

Explanation:

This question depicts OSMOSIS, which is a process whereby water moves from a region of low solute concentration to a region of high solute concentration via a semipermeable membrane.

According to this question, an animal cell is placed in an aqueous solution. The cell has a solute concentration of 6%, while the aqueous solution has a solute concentration of 18%. This means that the solute concentration of the extracellular solution is higher (hypertonic) than that of the cell (hypotonic), hence, water will move out of the cell into the aqueous solution, eventually causing the animal cell to SHRIVEL.

air enters through the nose, moves through the nasal cavity, the pharynx, the larynx, enters the trachea, moves through the bronchi andbronchioles till the alveoli.