If two heterozyotes for dwarfism have children what proportion of their kids would you expect to be of typical size and not exhibit dwarfism?

3/4 or 75%

Explanation:

This question involves a gene coding for height in humans. The allele for normal height (D) is dominant to the allele for dwarfism (d).

If two heterozygotes for dwarfism are crossed i.e. Dd × Dd, the following gamete will be produced by each heterozygote parent:

Dd - D and d

Using these gametes in a punnet square (see attached image), the genotypes of the expected offsprings will be as follows- DD (1) : Dd (2) : dd (1)

(1) DD - typical normal size

(2) Dd - heterozygous normal size

(1) dd - dwarf

The offsprings expected to be of typical size and not exhibit dwarfism are offsprings DD and Dd, which represent 3/4 of the offsprings. Hence, the proportion is 3/4 or 3/4 × 100 = 75%.

the answer is d. chordata