In a theoretical population in H-W equilibrium, 150/1000 have aa. For this population, what is p? what is q? Please answer honestly.

The correct answer is :

q = 0.387

p =  0.613

Explanation:

According to the Hardy Weinberg equilibrium, the frequency of alleles or genetic variation remains constant from generation to generation if there is no external disturbance. Equilibrium of such kind in the real-world not possible however it is found to be effective for a theoretical population. H-W equilibrium can be represented with the help of an equation:

P²+ 2pq+q² = 1

here,

p^2 =       AA (dominant same allele frequency)

2pq=Aa (heterozygous frequency)

q^2=aa (recessive similar alleles frequency)

so from the equation:

Frequency of aa = q^2 = 150/1000 = 0.15

Frequency of 'a' = q = square root of 0.15 = 0.387

Freuqency of 'A' = p = 1- 0.387 = 0.613

the answer is

c. parental

explanation:

yes you are doing it right great gob