If a DNA strand has 23 % guanine before semi conservative replication occurs, what percent Thymine will each new strand have after replication?

27%

Explanation:

DNA is a linear molecule composed of four nucleotide bases: adenine (A), cytosine (C), guanine (G), and thymine (T). Chargaff's rules state that adenine (A) always pairs with thymine (T), while guanine (G) always pairs with cytosine(C). In consequence, the amount of G should be equal to the content of C, while the amount of T should be equal to the content of A. In this case, the content of G is 23% and the content of C is also 23%, so the remaining content (A + T) is equal to 54% [100 - (23 + 23) = 54%], thereby content of A is equal to 27% and the content of T is also 27% (27 + 27 = 54%).

b

explanation:

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.