Callie did a lab during which she investigated the difference in cellular respiration rates between two different types of corn: germinating and non-germinating. A germinating seed is one from which a plant has started to grow. A non-germinating seed is usually dry and a new plant has not yet emerged. The data that she gathered are displayed in the graph. After Callie obtained her original results, she wanted to dig deeper. She determined that the germinating corn seed had utilized 100 molecules of glucose in the first few seconds that she performed the experiment. If these data are accurate, how many carbon dioxide molecules would Callie expect to have been released as a waste during this same amount of time? Explain how you arrived at your answer. The formula for cellular respiration is shown below. C6H12O6 + 6O2 → 6CO2 + 6H2O + energy This a written question and please keep it at 7th grade level

I might be wrong but im guessing 600

Explanation:

Since there is one molecule of glucose used per 6 molecules of carbon dioxide released, if you have 100 molecules of glucose, then you multiply the carbon dioxide by 100 which is 600. Thats what I would say but I might be wrong.

hey bro i looked it up on google the structure of the eye-spot in euglena viridie, e. ehrenbergii, and phacus pyriyorme is not as franzé haa described it. the so-called “crystal body” and “lens bodies” were not found in any of the individuals of the species examined by me. as earlier observers have stated, the eye-spot consists simply of a mass of pigment granules arranged in a single layer, and probably embedded in a protoplasmic framework, but the latter could not be seen, and its presence was only inferred from the fact that the pigment granules must be held together in some way, thd the eye-spot as a whole is capable of expansion, and that the pigment granules can be separated from each other.

hope this   and an i get brainlsiest