What is the resulting amino sequence if the following mRNA molecule undergoes translation 5’ AUG AGU CCU CUU UGA 3’ ?

From the translation of the mRNA molecule 5’ AUG AGU CCU CUU UGA 3’ results the amino acid sequence Met-Ser-Pro-Stop, that is, Methionine-Serine-Proline and the last triplet being a stop codon.

Explanation:

Messenger RNA (mRNA) molecule is in charge of conducting the encoded genetic information to produce the protein synthesis, organized in a sequence of nucleotides called the genetic code. The arrangement of the nucleotides is in triplets of bases or codons, which encode the synthesis of an amino acid (translation), determine the beginning of the synthesis and also establish the stop.

In the given sequence, 5’-AUG-AGU-CCU-CUU-UGA-3’ results the amino acid sequence Met-Ser-Pro-Stop:

Stop codons do not code for amino acids, but their presence in a codon sequence marks the completion of peptide or protein synthesis.

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