In pea plants, the allele for tall plants is dominant to the allele for short plants. if a homozygous tall plant is crossed with a homozygous short plant, what percent of offspring would you expect to be short? 0 percent 25 percent 50 percent 100 percent

First you build a Punnet Squares Diagram:
     |     |     |
     |     |     |
     |     |     |

We will be using TT for homozygous tall, and tt for homozygous short. Now you will imput TT along the top line, one letter per box. Do the same along the left side. It should look like this:
     |  T  |  T  |
  t  |      |      |
  t  |      |      |

Now you where the rows and columns meet, you will write both letters into the box. Make sure you always put capital letters first.
     |  T  |  T  |
  t  |  Tt |  Tt |
  t  |  Tt |  Tt |

When the letters are both capital, or lowercase, the gene in homozygous. When there is a capital and a lower case, it is heterozygous. Now as you can see on the diagram, all four boxes are heterozygous, so to answer the original question, you can expect 0% of the offspring to be short, because of the dominant gene making them tall.

Answer:

9.9 years

step-by-step explanation:

a = p(1 + rt) . . account balance after time t at rate r starting with principal p

3000 = 2500(1 + 0.0202t) . . filling in the given numbers

1.2 = 1 + 0.0202t . . divide by 2500

0.2 = 0.0202t . . . subtract 1

0.2/0.0202 = t ≈ 9.901

it will take about 9.9 years for the account balance to reach $3000.