A peony plant with straight stamens and red petals was crossed with another plant having straight stamens and streaky petals. The seeds were collected and germinated and the following offspring were obtained 62 straight stamens with red petals 59 straight stamens, streaky petals 18 incurved stamens, red petals 22 incurved stamens, streaky petals a) Which alleles in each pair are dominant

Explanation:

From the given information.

Let the Straight stamens be S;

The incurved stamens be s;

The red petals be R; and

The streaky petals be r

The genotype of the parental plants are Straight stamens, red petals (SsRr) and Straight stamens, streaky petals)

So if SsRr and Ssrr crossed together, Then we have the following:

If SsRr self crossed, we have the following traits  = SR  Sr sR sr; &

Ssrr = Sr Sr sr sr

Then, the dihybrid cross is:

           SR               Sr                      sR                     sr

Sr       SSRr             SSrr                  SsRr                 Ssrr

Sr      SSRr             SSrr                  SsRr                 Ssrr

sr      SsRr              Ssrr                  ssRr                 ssrr

sr      SsRr              Ssrr                  ssRr                 ssrr

P(Straight stamens, red petals) = 8/16

P(Straight stamens, streaky petals) = 6/16

P(Incurved stamens, red petals ) = 2/16

P(Incurved stamens, streaky stamens) = 2/16

c. would be the answer : )

explanation:

littering streams           is the answer