HELP PLEASE In the following cross, assume simple dominance and independent assortment for each trait. What proportion of the progeny will be expected to phenotypically resemble the second parent? AABB x Aabb

1. 1/4

2. 1/8

3. 3/4

4. 3/8

0

Explanation:

This question involves two genes; A and B. According to the question, two parents are crossed as follows: AABB × Aabb. The parents will produce the following gametes:

AABB- AB, AB, AB, AB

Aabb - Ab, Ab, ab, ab

Using these gametes in a punnet square (see attached image), the offsprings in the following proportion will be produced:

AABb = 4/16 = 1/4

AaBb = 4/16 = 1/4

Therefore, none (0) of the offsprings will resemble the phenotype of the second parent (Aabb).

a

explanation:

the dark variety, as they are not visible on the dark tree barks

explanation: