The ability to curl the tongue in dominant to the inability to do so. If Eric (heterozygous tongue curler) marries Brandy (also heterozygous) what are the predicted GTs and PTs of the offspring?

Genotype = 1CC: 2Cc: 1cc

Phenotype = 3 tongue curler : 1 non-tongue curler

Explanation:

This question involves a single gene that codes for the ability or not to curl the tongue. The ability to curl the tongue (C) is dominant to the inability to do so (c). This means that a heterozygote will be able to curl his/her tongue.

According to this question, If Eric, who is a heterozygous tongue curler (Cc) marries Brandy who is also heterozygous (Cc) i.e. Cc × Cc, the following gametes will be produced by each parent: C and c.

Using these gametes in a punnet square (see attached image), the predicted genotype of the offspring is 1CC: 2Cc: 1cc while the predicted phenotype is 3 tongue curler : 1 non-tongue curler.

answer: accepted answer: aquatic animals use the oxygen dissolved in water to carry out respiration. since the amount of dissolved oxygen in water is low as compared to the amount of oxygen in the air, therefore the rate of breathing in aquatic animals is much faster than it is in terrestrial animals.

explanation: