An athlete throws the javelin 212 m. The average speed of the javelin was 15 m/s. How long was the javelin in the air?

The correct answer is - 14.133 seconds.

Explanation:

The time that the javelin took in the air before landing after the 212 m throw can be calculated by simple distance and velocity formulas which say that the speed of an object is equal to the distance traveled by the object in unit time.

Given:

Speed or s = 15 m/s

Distance or d = 212 m

Then, the time or t =?

Solution:

By the formula, s = d/t

or t = d/s

t = 212/15

t = 14.1333

thus, the correct answer is - javelin was in the air for 14.1333 seconds.

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