A pure-breeding, tall pea plant with white flowers is crossed with a pure-breeding, short plant with red flowers. The F1 plants are tall, with red flowers. When allowed to fertilize themselves, these produce the following F2: 326 tall, red; 104 tall, white; 117 short, red; and 29 short, white. You are conducting a Chi-Square analysis and what is the null hypothesis?

Null Hypothesis -

The observed frequency is approximately equal to the expected frequency of phenotype.

Explanation:

Pure Breeding Cross - TTww x ttWW

Genotype of offspring in F2 generation - TtWw

Null Hypothesis -

The observed frequency is approximately equal to the expected frequency of phenotype.

The chi square analysis is attached

The degree of freedom for this question is 3

The p value for X^2 estimated through chi square test is 0.5

Hence the null hypothesis is accepted.

the dna molecules have a negative charge because of the phosphate groups in their sugar-phosphate backbone, so they start moving through the matrix of the gel towards the positive pole. power is turned on and dna fragments migrate through gel (towards the positive electrode).

explanation:

the correct answer is 2 and 4