What is the solute potential (ΨS ) of a 3.0 M NaCL solution at 27°C under standard atmospheric conditions?

149.58 bars

Explanation:

The solute potential (ΨS) of a solution is given by:

ΨS = iCRT

Where i = ionization constant of the solution, C = molar concentration of the solution, R = pressure constant =0.0831 liter bars/mole-K, and T = temperature in Kelvin.

NaCl dissociates in water to give Na and Cl ions, hence, i = 2

T = 27 + 273 = 300 Kelvin

C = 3.0 M

ΨS = 2 x 3 x 0.0831 x 300

         = 149.58 bars.

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