Jacky leaves the office at 4:15 PM. If she reaches her house at 4:55 PM
when her house is 25 km away from
her office, approximately, how fast did
she drive?

Given:

Jacky leaves the office at 4:15 PM and she reaches her house at 4:55 PM.

Distance between office and her house = 25 km

To find:

The driving speed of Jacky.

Solution:

The difference between 4:15 PM and 4:55 PM is 40 minutes.

60 minute = 1 hour

1 minute = hour

40 minute = hour

                 = hour

We know that,

Therefore, the driving speed of Jacky is 37.5 km per hour.

i think that the best answer would be c.

tell me if im wrong : )

i believe it would cause an increase of percipitation, though i could be wrong. so i would say b is the answer.