An individual has the genotype Aa Bb CC Dd ee FF. How many different types of gametes could it produce in terms of unique allelic combinations of these genes?

64

Explanation:

The individual in this question with genotype: Aa Bb CC Dd ee FF has six (6) different traits encoded by six (6) genes. The diploid number of the organism in this question is 12, however, the number of possible allelic combinations in each gamete can be calculated by using 2^n where n = haploid number of chromosome or number of allele that can be in one gamete.

Using this simple formula, 6 possible alleles can be in the gamete of this organism with the above genotype, hence, the individual can produce 2^6 = 64 different types of gametes in terms of unique allelic combinations of these 6 genes.