In a dihybrid cross, if the genotypes of one the parents is BbTT, what genes would you put on the outside of the Punnett square? Answers:

BT, Bt, BT, Bt

BT, BT, BT, BT

BB, bb, TT, tt

BT, BT, bT, bT

BT, BT, bT, bT

Explanation:

According to Mendel's law of independent assortment, the alleles of a gene will separate into gametes independently of one another i.e. one allele of a gene does not hinder the separation of another. The separation occurs via meiosis in such a way that only one allele of a gene is present in each GAMETE.

These gametes are what forms the crossing basis in a punnet square. According to this question involving a dihybrid cross, the genotype of one of the parents is BbTT. The allelic combination of the gametes will be: BT, BT, bT, bT. These gametes will be put on the outside of the Punnett square.

BT,BT,bT,bT

Explanation:

It's 50/50.

desert perennials often survive by remaining dormant during dry periods of the year, then springing to life when water becomes available. most annual desert plants germinate only after heavy seasonal rain, then complete their reproductive cycle very quickly.