Estimate the electric field in the membrane wall of a living cell. Assume the wall is 14 nmnm thick and has a potential of 0.11 VV across it.

The electric field in the membrane wall of a living cell is 7.857 x 10⁶ V/m.

Explanation:

Given;

thickness of the membrane wall, d = 14 nm = 14 x 10⁻⁹ m

potential of the membrane wall, V = 0.11 V

The electric field in the membrane wall of a living cell is calculated as;

Therefore, the electric field in the membrane wall of a living cell is 7.857 x 10⁶ V/m.

d.

explanation:

ionic bonds are two oppositely charged ions that attract. a sodium ion has a 1 positive charge; a chloride ion has a 1 negative charge. sodium and chloride have oppostive charged ions that attract which forms an ionic bond. a chemical bond formed when two atoms share electrons is called