You are studying a new gene "X" that you think controls skin color in Bearded Dragons. In order to determine what gene X does you need lots of gene X DNA to work with. So, you decide to amplify it through the process known as PCR. You have a forward and a reverse primer that have been designed to gene Xf – a gene in frogs that is similar to the one found in the Bearded Dragon. You are pretty sure that these two primers will work in Bearded Dragons, so you decide to go ahead with the PCR. In frogs, the Forward Xf primer binds gene Xf between nucleotides 32 and 47. The Reverse Xf primer binds between nucleotides 1110 and 1135. What size PCR product would these two primers create if they amplified the frog gene Xfp

The correct answer is - 1103 bp.

Explanation:

PCR or polymerase chain reaction is a process that uses a primer to amplifying the desired segments of DNA molecules. It is a technique that can amplify a million copies of the DNA segment.

given:

forward primer binds from - 32 to 47

reverse primer binds from - 1135 to 1110

PCR product would be between - 32 to 1135

So, product size would = 1135-32 = 1103.

Thus, the correct answer is - 1103.

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hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.