In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.2. What is the frequency of individuals with Aa genotype? will reward for best answer with explanation...please no more links or i will report

0.42

Explanation:

To estimate the frequency of alleles in a population, we can use the  

According to this equation:-

p =  

q =  

p + q = 1.0  

(p + q)  

2

 = 1 so p  

2

 + 2pq + q  

2

 = 1

p  

2

2pq = frequency of Aa  

q  

2

p+q = 1

0.3 + q = 1

q = 1 - 0.3 = 0.7

Aa = 2pq = 2* 0.3 * 0.7 = 0.42.

haploid cells;

easy

explanation: