Apopulation of 150 individuals has an allele frequency of 0.2 for the dominant allele (h) and a frequency of 0.8 for the recessive allele (h). use the hardy-weinberg equation to determine the frequencies of the three genotypes:
p^2 +2pq+q^2=1

f(hh) = p2 =

f(hh) = 2pq =

f(hh) = q2 =

A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recessive allele (h). Use the Hardy-Weinberg equation to determine the frequencies of the three genotypes:

f(HH)  =  p2   =   0.04

f(Hh)  =   2pq  =   0.32

f(hh)  =   q2   =   0.64

Explanation:

just got it from EdgE

hello there the answer is d