You may have heard through various media of an animal alleged to be the hybrid of a rabbit and a cat. Given that the cat (Felis domesticus) has a diploid chromosome number of 38 and a rabbit (Oryctolagus cuniculus) has a diploid chromosome number of 44, what would be the expected chromosome number in the somatic tissues of this alleged hybrid

The correct answer is - 2n = 41 chromosomes.

Explanation:

It is given that the cat has a diploid chromosome number of 38 while the rabbit has a diploid number of 44 chromosomes and if they form a hybrid then their expected chromosome number in somatic cells would be -

Cat (2n=38) produces haploid gametes with 19 chromosomes (n-19).

Rabbit (2n=44) produces haploid gametes with 22 chromosomes(n=22)

19+22= 41 chromosomes in the particular hybrid as half number of chromosomes come from each parent.

hey bro i looked it up on google the structure of the eye-spot in euglena viridie, e. ehrenbergii, and phacus pyriyorme is not as franzé haa described it. the so-called “crystal body” and “lens bodies” were not found in any of the individuals of the species examined by me. as earlier observers have stated, the eye-spot consists simply of a mass of pigment granules arranged in a single layer, and probably embedded in a protoplasmic framework, but the latter could not be seen, and its presence was only inferred from the fact that the pigment granules must be held together in some way, thd the eye-spot as a whole is capable of expansion, and that the pigment granules can be separated from each other.

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well for one plants are always the producer, so a is the answer. a wolf is more of the consumer(predator) and the deer is the prey so i know those two are out of the question. also mushrooms are fungi/fungus so a is the producer.