When calcium carbonate is heated, it decomposes into calcium oxide and carbon
dioxide. If 100 g of calcium carbonate are
decomposed, 56 g of calcium oxide is produced.
What would be the mass of the carbon dioxide
given off by the decomposition?
A. 448
B. 110 g
C. 156 g

A. 44 g

Explanation:

First, you need to write a balanced equation:

CaCO₃ -> CaO + CO₂

Then, you need to find the molar mass of CaCO₃:

Ca = 40.078 amu

C = 12.0107 amu

3O = 47.9982 amu

100.0869 amu

Then, you calculate the moles of CaCO₃:

100 g ÷ 100.0869 amu = 0.9991 moles

In the balanced equation, we can see that the molar ratio of CaCO₃ and CO₂ is 1 : 1, so moles of CaCO₃ = moles of CO₂.

Now you need to find the molar mass of CO₂:

C = 12.0107 amu

2O = 31.9988 amu

44.0095 amu

Finally, you can calculate the mass of CO₂ produced:

0.9991 moles * 44.0095 amu = 43.9698 g = 44 g

relative humidity, temperature and dew point -- are bound together in the mathematical relationship below. relative humidity changes when temperatures change. because warm air can hold more water vapor than cool air, relative humidity falls when the temperature rises if no moisture is added to the air. so i would say a

the answer to your question is:

c. complementary base-pairing