How high is the ceiling in a school gym if a volleyball thrown upward from the floor at 15 m/s barely touches the ceiling before returning to the ground?

The height of the ceiling in the school gym from the floor is 11.48m.

HOW TO CALCULATE HEIGHT OF A PROJECTILE:

v² = u² + 2as

Where;

v = final velocity (m/s)

u = initial velocity (m/s)

a = gravitational acceleration (m/s²)

s = distance traveled (m)

According to this question,

Using the formula, v² = u² + 2as, the height of the ceiling (s) can be calculated as follows:

15² = 0² + 2 (9.8) (s)

225 = 0 + 19.6s

225 = 19.6s

s = 225/19.6

s = 11.48m

Therefore, the height of the ceiling in the school gym from the floor is 11.48m

Learn more:

11.47 m

Explanation:

Givens

vi =   15 m/s

a = - 9.81 m/s^2

vf = 0

d = ?

Formula

vf^2 = vi^2 + 2ad

Solution

0 = (15)^2 + 2*(-9.81)*d

- 225 = 2 * - 9.81 *d

-225 = - 19.62 * d

d = - 225/-19.62

d = 11.47 m

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multiplying and dividing the two decimals and the eqations by the same number of the overalls