Awoman is heterozygous for blue eyes. if she were to have child with a man who is homozygous recessive for brown eyes, what is the probability of this child having blue eyes? 0% 25% 50% 75%

50%

Explanation:

According to the given information, the woman is heterozygous for blue eyes. It means that the blue eye color is a dominant trait over brown eyes since heterozygous carrier genotypes are present for dominant alleles only.

Let's assume that the allele for blue eye color is "B" and the one for brown eye color is "b". Therefore, the genotype of heterozygous woman would be "Bb" and the genotype of the homozygous recessive male would be "bb".

A cross between Bb x bb gives following phenotype ratio = 50% brown eye : 50% blue eye

There is 50% probability of their child to have blue eye color.

it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.

not necessarily. higher fitness requires the organism to be reproductive successful. for example, an organism at age 10 with 15 offspring is much more fit than an organism at age 15 with only 5 offspring.