Okay consider a cross of beetles with exoskeleton allies b and b and leg size alleles n and n. the male parent is heterozygous in both traits. the females parent is homozygous recessive in both traits

Answer

This cross will generate puppies with the genotypes of 25% BbNN, 25% Bbnn, 25% bbNn and 25% bbnn.

Explanation:

In this case the parent beetle has genotype BbNn and the mother beetle is bbnn. To solve this intersection, we have to remember Mendel's law of independent segregation and perform the traits intersections separately and multiply the percentages later.

1 - Characteristic of the exoskeleton: Bb x bb that gives us 50% Bb, 50% bb.

2 - Leg feature: Nn vs nn which gives us 50% Nn and 50% nn as well.

Finally, that means the cross of beetles have a chance to origin puppies with (0,5 * 0,5) in each different trait, resulting in the genotypes of 25% BbNN, 25% Bbnn, 25% bbNn and 25% bbnn

tsd is temerature dependent sex determination.

tsd: it is a type of environmental sex determination in which the temperature experienced during embryonic/ larval development (ambient temperature for development) determine the sex of the offspring.

crocodile displays the tsd where the ambient temperature of the developing egg determines the individual's sex. for example in the american alligator's eggs, incubation at 33 ºc produces mostly males, while incubation at 30 ºc produces mostly females. so if the american alligator's egg will get the ambient temperature (33 degree celcius)during embryonic development from egg, the offspring will be male and same for the female sex determination.

i think the answer would be d