In chickens a flat single comb is a recessive trait while short thick rose comb is dominant. in a particular population of chickens 45 are homozygous for the dominant trait 30 are heterozygous dominant and 25 have the recessive trait. which expression is the correct way to calculate the frequency of the recessive allele? a-80/100 b-80/200 c-55/100 d-55/200 e-120/200

The correct answer would be B-80/200.

Allele frequency is defined as relative occurrence of the allele at a particular locus in a given population.

We have a sample population of 100 chickens where

Frequency of homozygous dominant trait (CC) =  45

Frequency of homozygous recessive trait (cc) = 25

Frequency of heterozygous dominant trait (Cc) = 30

Total alleles would be = 100 x 2 = 200

Total number of observed copies of C (dominant allele) = (45 x 2) + 30 = 120

Similarly, number of observed copies of c (recessive allele) = (25 x 2) + 30 = 80.

Hence, the frequency of allele C = 120/200 = 0.6

Frequency of allele c = 80/200 = 0.4

answer; i believe the correct answer is (anemia);

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