The presence of freckles is due to a dominant allele. four percent of the individuals in a particular population lack freckles. use the hardy-weinberg formula to calculate the percentage of individuals in this population who are homozygous dominant for freckles

Let us assign the recessive allele for freckle to be f and the dominant F. According to the statement, we deduce that ff = 0.04.

The frequency of the recessive f allele is, therefore, is 0.2 (square root of 0.04 ).

Hardy-Weinburg p + q = 1

P + 0.2 = 1; p = 1- 0.2 = 0.8

Therefore using the Hardy-Weinburg equation of a population in equilibrium

P2+2pq+q2=1

Heterozygous individuals are;

2pq = 2*0.8*0.2 = 0.32

This is 32% of the population

clinically, some people often have repeated allergies, eczema and respiratory infections or other parts of the infection, in this case, in addition to some routine tests such as tests for white blood cells, immunoglobulin series, lymphocyte subsets, etc., the five immune immunoglobulin tests are also necessary.