R14: why will two isps at the same level of the hierarchy often peer with each other? how does an ixp earn money?

In order to be thoughtful about the implementation of security policies and controls, leaders must balance the need to with the impact to the business operations. doing so could mean phasing security controls in over time or be as simple as aligning security implementation with the business’s training events.

Add the mips assembly language instructions (after main: ) to complete the following (in this order). do not skip steps. use other registers as needed. actions: 1. initialize the register $s0 to 35 2. prompt the user to enter a number, read the number and then put it into register $s1 3. prompt the user to enter a number, read the number and then put it into register $s2 4. store the value in $s1 into the memory at address 0x10010000. 5. store the value in $s2 into the memory at address 0x10010004. 6. calculate the value of $s0 - $s1 $s2 and store the result in the memory at address 0x10010008. 7. print the following output each on its own line. you will need to determine the location of each of the strings from the beginning of the memory segment a. your name b. the value in address 0x10010000 c. the value in address 0x10010004 d. the value in address 0x10010008 8. exchange or swap the values in $s1 and $s2 9. set the value in $s0 to -$s0

Kenney co. uses process costing to account for the production of canned energy drinks. direct materials are added at the beginning of the process and conversion costs are incurred uniformly throughout the process. equivalent units have been calculated to be 19,200 units for materials and 16,000 units for conversion costs. beginning inventory consisted of $11,200 in materials and $6,400 in conversion costs. april costs were $57,600 for materials and $64,000 for conversion costs. ending inventory still in process was 6,400 units (100% complete for materials, 50% for conversion). the total cost per unit using the weighted average method would be closest to: