Business, 26.06.2019 20:20 pawfox

Each step in the following process has a yield of 80.0%. ch4+4cl2⟶ccl4+4hcl ccl4+2hf⟶ccl2f2+2hcl the ccl4 formed in the first step is used as a reactant in the second step. if 2.00 mol ch4 reacts, what is the total amount of hcl produced? assume that cl2 and hf are present in excess.

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Each step in the following process has a yield of 80.0%. ch4+4cl2⟶ccl4+4hcl ccl4+2hf⟶ccl2f2+2hcl the...

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