The fares received by taxi drivers working for the City Taxi line are normally distributed with a mean of $12.50 and a standard deviation of $3.25. Based on this information, what is the probability that a specific fare will exceed $15.00?

0.2308 or 23.08%

Explanation:

Mean (μ) = $12.50

Standard deviation (σ) = $3.25

Assuming a normal distribution, for any given fare X, the z-score is calculated as:

For X = $15.00, the z-score is:

A z-score of 0.7692 corresponds to the 77.91-th percentile of a normal distribution. Therefore, the probability that a fare exceeds $15.00 is:

The probability that a specific fare will exceed $15.00 is 0.2308.

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answerpounds of plastic to purchase 200+60-20=(240);