The owner of Touchdown Sports Bar wants to develop a time standard for the task of mixing a specialty cocktail. In a preliminary study, he observed one of his bartenders perform this task seven times with an average of 90 seconds and a standard deviation of five seconds. What is the standard time for this task if the bartender worked at a 20 percent faster pace than is average, and an allowance of 10 percent of job time is used

Standard time = 118.8 second

Explanation:

given data

observed time = 90 seconds

Allowance factor = 10% = 0.10

standard deviation = 5 seconds

bartender worked = 20 percent

solution

we get here average observed time that is express as

average observed time =  90 × 1.20

average observed time = 108 seconds

and standard time for the task that is express as

Standard time = Average observed time × (1 + Allowance factor)

Standard time = 108 × (1 + 0.10)

Standard time = 108 × 1.10

Standard time = 118.8 second