Business, 15.02.2020 02:07 rbeltran24

Automobile alliance has determined that dealerships are actually heavily discounting the price of the Family Thrillseekers to move them off the lot. Because of a profit-sharing agreement with its dealers, the company is therefore not making a profit of $3600 on the Family Thrillseeker but it's instead making a profit of $2800. Determine the number of Family Thrillseekers and the number of Classy Cruisers that should be assembled given this new discounted price

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Answer from: muravyevaarina

Rachel should have 1875 Family Thrillseekers and 3500 Classy Cruisers assembled for a maximum profit of $24,150,000.

Explanation:

As the question is not complete, by searching the question statement, a similar question is found so that complete data is used so

Let the number of Classy cruisers be X

Let the number of Family Thrillseeker is Y

The profit on classy cruisers is given as $5400.(from complete question)

The profit on Family Thrillseeker is as given $2800.

The maximizing function is

$Z=\$5400X+\$2800Y$

The constraints are as follows

The first constraint is as The plant has a capacity of 48,000 labor-hours per month. It takes 6 labor-hours to assemble one Family Thrillseeker and 10.5 labor-hours to assemble one Classy Cruiser. given as

10.5X+6Y $\leq$ 48000

The second constraint is as Rachel will only be able to obtain 20,000 doors (10,000 left and 10,000 right) from the door supplier, the Family Thrillseeker(2 Left & 2 Right) and the Classy Cruiser(1 Left and 1 Right) use the same door part. Given as

2X+4Y $\leq$ 20000

The third constraint is as A company forecast suggests that the demand for the Classy Cruiser is limited to 3500 cars, and there is no limit on the demand of the Family Thrillseeker. Given as

X $\leq$ 3500

Using the plots of constraints corresponding equations and solving for the corner points as given below

P1(0,0)

P2(0,5000)

P3(2400,3800)

P4(3500,1875)

P5(3500,0)

For each of the above values, the value of function Z is calculated and maximized accordingly

$Z(0,0)=\$5400(0)+\$2800(0) =0$

$Z(0,5000)=\$5400(0)+\$2800(5000) =14000000$

$Z(2400,3800)=\$5400(2400)+\$2800(3800) =23600000$

$Z(3500,1875)=\$5400(3500)+\$2800(1875) =24150000$

$Z(3500,0)=\$5400(3500)+\$2800(0) =18900000$

In this case Rachel should have 1875 Family Thrillseekers and 3500 Classy Cruisers assembled for a maximum profit of $24,150,000.

Automobile alliance has determined that dealerships are actually heavily discounting the price of th

Answer from: Quest

How can we answer it? we need more info on the question lol.

Answer from: Quest

Idon’t know what to do it

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