As part of a time study a particular job was analyzed. The study included 20 job cycles and the following cumulative times and performance rating factors for each element were reported St (min) 54.64 49.67 42.98 51.37 RF 1.05 1.10 0.95 0.95 Element 4 Assuming an allowance factor of 20% the standard time for this job would be .

A. 16.58 minutes
B. 12.10 minutes
C. 10-08 minutes
D. 14.73 minutes

The correct option is B.

The standard time for this job would be 12.10 minutes.

Explanation:

Element  |  St(min)   |    RF       |   AOT   |    NT    

   1          |   54.64    |    1.05     |   2.73   |   2.86

   2         |   49.67    |    1.10      |   2.48   |   2.72

   3         |   42.98    |    0.95    |   2.14    |   2.03

   4         |   51.37     |    0.95    |   2.56   |   2.43

The standard time for the job is calculated by

Standard time = Total normal time*(1 + allowance factor)

Where Normal time is given by

Normal time = Average observation time * Rating Factor (RF)

Where Average observation time is given by

Average observation time = St(min)/number of job cycles

number of job cycles = 20

Total Normal time = 2.86 + 2.72 + 2.03 + 2.43

Total Normal time = 10.04 minutes

Standard time = 10.04*(1 + 0.20)

Standard time = 12.04 minutes

Therefore, the correct option would be B, the standard time for this job would be 12.10 minutes.

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