Business, 19.02.2021 16:40 abelxoconda

Gubser Welding, Inc., operates a welding service for construction and automotive repair jobs. Assume that the arrival of jobs at the company's office can be described by a Poisson probability distribution with an arrival rate of five jobs per 8-hour day. The time required to complete the jobs follows a normal probability distribution, with a mean time of 1.3 hours and a standard deviation of 1 hour. Answer the following questions, assuming that Gubser uses one welder to complete all jobs: What is the mean arrival rate in jobs per hour? Round your answer to four decimal places.
jobs per hour
What is the mean service rate in jobs per hour? Round your answer to four decimal places.
jobs per hour
What is the average number of jobs waiting for service? Round your answer to three decimal places.

What is the average time a job waits before the welder can begin working on it? Round your answer to one decimal place.
hours
What is the average number of hours between when a job is received and when it is completed? Round your answer to one decimal place.
hours
What percentage of the time is Gubser's welder busy? Round your answer to the nearest whole number.
% of the time the welder is busy.

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Answer from: bgallman153p71edg

a) Mean arrival rate in jobs per hour = 0.6250

b) Mean service rate in jobs per hour = 0.7692

c) The average number of jobs waiting for service = 2.802

d) Average time a job waits before the welder can begin working on it = 4.5 hours

e) Average number of hours between when a job is received and when it is completed = 5.8 hours

f) Percentage of the time is Gubser's welder busy = 81%

Explanation:

As given,

Number of jobs = 5

Rate = 8 hour per day

Average hours = 1.3

Standard deviation - 1 hour

Mean arrival = $\frac{No. of jobs}{rate}$

= $\frac{5}{8}$ = 0.6250 per hour

⇒Mean arrival rate in jobs per hour = 0.6250

Mean service rate = $\frac{hour}{average hour}$

= $\frac{1}{1.3}$ = 0.7692 per hour

⇒Mean service rate in jobs per hour = 0.7692

Average number of job waiting for service = $\frac{(0.6250)^{2} (1)^{2} + \frac{0.6250}{0.7692} }{2 ( 1 - \frac{0.6250}{0.7692} )}$

= $\frac{1.05}{0.375}$ = 2.802

⇒The average number of jobs waiting for service = 2.802

Average time a job waits before the welder can begin working on it = $\frac{2.802}{0.6250}$

= 4.5 hr

⇒Average time a job waits before the welder can begin working on it = 4.5 hours

Average number of hours between when a job is received and when it is completed = 4.5 + $\frac{1}{0.7692}$

= 4.5 + 1.3

= 5.8 hours

⇒Average number of hours between when a job is received and when it is completed = 5.8 hours

Percentage of the time is Gubser's welder busy = $\frac{0.6250}{0.7692}$ ×100%

= 0.8125×100%

= 81.25% ≈ 81%

⇒Percentage of the time is Gubser's welder busy = 81%

Answer from: Quest

okay lol !

Answer from: Quest

The letter c i’m pretty sure

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Gubser Welding, Inc., operates a welding service for construction and automotive repair jobs. Assume...

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