Podunk tech university's office of student affairs would like to estimate the proportion of podunk tech's students who have smoked marijuana in the past month. the office of student affairs would like to estimate the population proportion p to within .04 with 95% confidence.

600

Explanation:

Requirement "What sample size is required if the Office of Student Affairs has no knowledge of the approximate value of p? (Round your answer up to the next largest integer)."

Margin of error, m = 0.04

Confidence level, 1-∝=0.95

Assume that p = 0.5 as proportion is not given.

At 95% confidence(∝=0.05). the tabulated value from the z-table is 1.96

n = p(1-p)[z∝/m]^2

n = (0.5)(1-0.5)[1.96/0.04]^2

n = (0.5)(0.5)(2401)

n = 600.25

n = 600

So, the required samplesize would be 600

explanation:

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